1990 U.S. Open: Hale Irwin wins at Medinah C.C.
Hale Irwin won the 1990 U.S. Open at Medinah C.C. in Medinah, Illinois with 280 (−8), beating Mike Donald in a playoff.
Updated October 23, 2026
See 1990 in the U.S. Open room, or every year on the U.S. Open winners list.
- Dates
- June 14, 1990 to June 18, 1990
- Course
- Medinah C.C., Medinah, Illinois
- Edition
- 90th U.S. Open
- Champion
- Hale Irwin · USA · born Joplin, Missouri, USA
- Champion's title
- 3rd U.S. Open title
- Winning score
- 280 (−8)
- Runner-up
- Mike Donald
- Playoff
- 18 holes + sudden death (91st hole)
Winner and runner-up
| Pos. | Player | Total | To par |
|---|---|---|---|
| 1 | Hale Irwin | 280 | −8 |
| 2 | Mike Donald |
What happened at the 1990 U.S. Open
Irwin was in the field on a special exemption. He became the oldest champion by beating Donald on the 91st hole.
How this was built
Every value is shown as recorded in GNN's U.S. Open data. A value no source confirmed is left out; nothing is estimated. Where sources disagree, the organizer's own record is used.
Data: us-open-years.json (the U.S. Open room's data); dates from GNN's U.S. Open final-day dates table (Wikipedia infoboxes).